42 4 − 12 = 24 4 = 24 + 12 4 = 36 = 9 Jadi, nilai = 9 2. Penyelesaian persamaan kuadrat 2x + 4y + 2 = 0 dan 3x – y – 11 = 0 adalah x1 dan y1. Nilai x1 + y1 adalah .... Jawab: 2x + 4y + 2 = 0| × 3| 6x + 12y + 6 = 0 3x – y – 11 = 0 | × 2| 6x – 2y – 22 = 0 – 14y +28 = 0 14y = –28 y1 = –2 2x + 4y + 2 = 0 2x + 4(–2) + 2 = 0 2x – 8 + 2 = 0 2x = 6 x1 = 3 Jadi x1 + y1 = 3 + (-2) = 1 3. Jika 2 + 4 = 14 dan = 5 . Tentukan nilai .. Jawab: 2(5 ) + 4 = 14 = 5 10 + 4 = 14 = 5(1) 14 = 14 = 5 = 1
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