Indriyani Rebet - Kalkulus Terapan (Edisi Revisi)

140 �1 + � 2 = � + �2 = →( + )2 = 3 Contoh 2: =2 +3 2 2+2 → ini adalah PD homogin berderajat 2 = = + + = 2 . + 3 2 2 2 + 2 . = 2(2 + 3 2) 2(1 + 2 ) + =2 +3 2 1+2 = 2 + 3 2 1 + 2 − = 2 + 3 2 − −2 2 1 + 2 = 2 + 1 + 2 1 = 1 + 2 2 + �1 =�1 + 2 2 + = ln( 2 + ) + = ( 2 + ) → = � 2 2 + �= ( 2 + 2 ) + =

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