15 = (3 2 + 4) sin(4 −5) 52 −3 = (3 2 + 4) +lnsin(4 −5) + 52 −3 = (3 2 + 4) +lnsin(4 −5) + 52 −3 = (3 2 + 4) +ln sin(4 −5) + (2 −3) 5 1 =3 1 2+4 6 +sin 1 (4 −5) 4 cos(4 −5) + 2. 5 = (3 1 2+4 6 +sin 1 (4 −5) 4 cos(4 −5) + 2. 5) = (3 2 + 4) sin(4 −5) 52 −3( 6 3 2 + 4 + 4 co (4 −5) + 2. 5) 2. =(3 +7).tan 2 cos (2 −3) = ln(3 + 7) + 2 − (2 −3) 1 = (3 3 + 7) + 1 2 2 22 + cos (2 1 −3) . 2sin (2 −3) = [ (3 3 + 7) + 1 2 2 22 + cos(2 1 −3) . 2 sin(2 −3)] =(3 +7).tan 2 cos (2 −3) [ 3 (3 +7) + 1 2 2 22 +cos 1 (2 −3) . 2 sin(2 − 3)] 2.1.2.6.
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