47 = (3 + 2 ). (3 + 0) = 3 (3 + 2 ) = (3 + 2 )(0 + 2) = 2 (3 + 2 ) Sekarang kita differensialkan sekali lagi terhadap . ℎ 2 2 = 3. �− (3 + 2 )�.3 =−9 (3 + 2 ) � �= 2 = 3. �− (3 + 2 )�. 2 =−6 (3 + 2 ) � ∂ Z ∂y� = ∂2Z ∂x∂y =−2. �sin(3x + 2y)�. 3 =−6sin(3x + 2y) ∂ ∂ y� ∂ Z ∂y� =∂2Z ∂y2 =−2. �sin(3x + 2y)�. 2 =−4sin(3x + 2y) 2.4.1. Latihan soal 1. Differensialkan terhadap variabel bebasnya (differensial pertama saja) a. = ( , ) = tan (2 2+5 2) b. = ( , ) = (3 + 2 ) c. = ( , ) =sin ( 3 −2
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