93 Contoh Soal 7.2 Diketahui: = 60 + 40 Ω; 0 =50Ω Ditanyakan: =? Jawab: • = 60 + 40 Ω = 0,35 < 58,220 1 = 58,220 7200 = 0,078 = 1 1 + 0,35 −0,35 = 2,08 ′= 2,08(50) = 103,84Ω � 4� =�103,84(50) ≈ 72Ω 1→ 1 = 0,078 � 4� =72Ω 2→ 2 = 0,078 + 0,25 = 0,328 � 4� = 502 72 = 34,7Ω • = 60−40 Ω = 0,35 <−58,220 1 = 0,25 −58,220 7200 = 0,25 −0,078 = 0,172 ′= 50/2,08 =24Ω � 4� =�24(50) ≈34,7Ω 1→ 1 = 0,172
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